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Are electrons the only thing that emits light? |
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| Aug3-09, 01:08 AM | #1 |
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Are electrons the only thing that emits light?
WARNING NOOB QUESTION FOLLOWS:
Well this has been bugging me lately, as i have been doing research on maxwells equations. In chemistry i was taught that light from chemical reactions comes from electrons jumping from a higher orbit to a lower one. But is ALL light emitted this way, or only light that comes from chemical reactions? For instance, are the electrons in my desk always jumping to create the brown color of wood? In my research i found that a changing electric field creates a magnetic field that also is changing to create an electric field. And this creates light. I do not doubt that the electrons jumping down an orbit gives off light, but is the only thing that gives off light? This would mean all object's electrons jump from the exact same point to give off the exact same color at all times. |
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| Aug3-09, 02:14 AM | #2 |
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For visible light, I think you can say safely that most of visible light you will ever see has to do with moving electrons, yes.
In principle, every charged particle can emit light by moving, but from the top of my head, I can't think of many that produce actual *visible* light and aren't electrons. |
| Aug3-09, 02:17 AM | #3 |
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That just doesnt seem right to me. |
| Aug3-09, 04:33 AM | #4 |
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Are electrons the only thing that emits light? |
| Aug3-09, 04:49 AM | #5 |
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Mentor
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| Aug3-09, 04:52 AM | #6 |
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Thanks. This time I'll remember it.
Weird how that turns the light off in neutron stars :P |
| Aug3-09, 08:42 AM | #7 |
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"In 1965, Antony Hewish and Samuel Okoye discovered "an unusual source of high radio brightness temperature in the Crab Nebula." - Wikipedia
Some more info could be found here, have fun
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| Aug3-09, 09:23 AM | #8 |
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Light and electromagnetic energy comes from vibrations of molecules and lattices, which is not vibration of a single nucleus, but of one nucleus in relation to another. Stuff is generally held together by electromagnetic forces of one kind or another, and the distributions of charge in a substance are not uniform from nucleus to nucleus. For example, a co-valent bond often has a disparity of charge to one of the nuclei involved, and so oscillations of the particles produce and absorb electromagnetic radiation. The charge differences are still about how the electrons are shared in the bonds. Cheers -- sylas |
| Aug3-09, 12:40 PM | #9 |
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This is a very good question. Everything we can see outside of cosmology is based on radiation from electrons in some way or another. The only thing atomic nuclei do is by holding electrons together in atomic states and by neutralizing the huge Coulomb forces of electrons alone.
I can name two sources of light created by atomic nuclei (outside of radioactive decay). Any charged particle traveling faster than c/n in a material (water, glass, plastic, etc.) with index of refraction n will radiate. This is called Cerenkov (also spelled Cherenkov) radiation. Electron Cerenkov radiation is easily seen in pool-type reactors and in used radioactive fuel rods stored under water. I have used equipment to detect visible photons from Cerenkov radiation from protons, kaons, muons, and pions. Any relativistic charged particle that is deflected with a strong magnetic field will radiate synchrotron radiation. Electrons do it. In the Superconducting Super Collider (cancelled), proton synchrotron radiation was a serious problem, This might also be true in the CERN LHC. |
| Aug3-09, 01:18 PM | #10 |
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Second example indeed ! |
| Aug3-09, 01:28 PM | #11 |
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Mentor
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QM tells us that the electron has a definite energy before the transition, according to which orbital the electron is in; but it does not tell us where, precisely, the electron is. It gives us only a probability distribution for finding the electron in various locations near the nucleus. Similarly after the transition, QM tells us that the electron has a definite (different) energy, according to which orbital the electron is now in; but again it gives us only a (different) probability distribution for the location of the electron. |
| Aug3-09, 01:43 PM | #12 |
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To be clear, I'm not saying this is true only of brown objects, I'm just saying it is especially obvious in that case because the color brown could not possibly be produced by a stream of a single type of photon. |
| Aug3-09, 02:06 PM | #13 |
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| Aug3-09, 02:19 PM | #14 |
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One of the major unsolved problems in the SuperConducting Supercollider was UV proton synchrotron radiation dislodging atoms of residual gas that had adhered to the walls of the 2 Kelvin vacuum tube, thus raising the residual gas pressure to an untenable level..Maybe this will be a problem in the LHC. We shall see...... |
| Aug3-09, 03:23 PM | #15 |
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Woah! lots of good information here. Some of it i didn't umderstand because im only 16 and still havent even taken physics class (taking it this yea when school starts up again, and thats why i said "in my research" instead of "in school").
It seems all my questions spark debates which lead the conversation off topic, but in doing so i learn even more. But i was able to fully understand LeonhardEuler's answer and now i understand. And i am very grateful for everyone else's replies also which gave me more interesting things to research. I can always rely on Physics Forums for a good answer and more! |
| Aug3-09, 11:58 PM | #16 |
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