# Calculating how to overcome drag

by rosie_burk
Tags: drag, overcome
 P: 623 Drag force is proportional to the cross-sectional area and velocity of the object. Since the drag coefficient remains the same, we can effectively ignore it. Thus it is clear that when I double cross-sectional area or velocity, the magnitude of the drag force would be doubled as well. When both are doubled simultaneously, the drag force is quadrupled to 40N. The relation between old and new drag force would be: $$\frac{F_{1}}{F_{2}} = \frac{A_{1} v_{1}}{A_{2} v_{2}}$$ The drag coefficient cancels out, so there is no need to include it. And, 24*1000=2400?? Do take more effort in putting forth your attempt here...