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dimensional alalysis to show functional dependence |
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| Oct11-09, 02:29 PM | #1 |
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dimensional alalysis to show functional dependence
1. The problem statement, all variables and given/known data
Use the method of dimensional analysis to show that the functional dependence in equation (1) can be derived from an observational expression: [TEX]lambda = k*mu*f^m*T^n[/TEX]. 2. Relevant equations [TEX]lambda=k\sqrt {{\frac {T}{\mu}}}{f}^{-1}[/TEX] (1) [TEX]lambda = k*mu*f^m*T^n[/TEX] [TEX]\mu={\frac {{\it kg}}{m}}[/TEX] [TEX]T={\frac {{\it kg}\,m}{{s}^{2}}}[/TEX] 3. The attempt at a solution First I solve for n. [TEX]m={\frac {{m}^{n}}{m}}[/TEX] n = 2 Now I solve for m. [TEX]0=0={1/s}^{m}{s}^{-2\,n}[/TEX] m = -4 so now I have: [TEX]\lambda={\frac {ku{T}^{2}}{{f}^{-4}}}[/TEX] I don't understand what the question means by "show that the functional dependence in equation (1). . ." In equation (1) we were told that [TEX]\lambda[/TEX] and T were variables. Well in equation I've derived [TEX]\lambda[/TEX] and T could very well be variables, but I don't think I understand the question. But, if the question is asking me to equate the two expressions and prove an "identity", then I can't do that. Any help welcomed and appreciated. When I try to "work" the units out they don't work out at all. |
| Oct11-09, 02:31 PM | #2 |
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I tried to make it all pretty with the LaTeX, but it didn't work :(
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| Oct11-09, 02:55 PM | #3 |
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Misread question. I thought the u had an exponent of 1, but it had an exponent of L.
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