What is the magnitude of the magnetic field of the wire

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Homework Help Overview

The discussion revolves around calculating the magnitude of the magnetic field generated by a long straight conducting wire carrying a current. The wire has a diameter of 6mm and the current is 4A. Participants are examining two specific points: one 1mm inside the surface of the wire and another 2cm from the center of the wire.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply Ampère's law to find the magnetic field at specified points, while some participants question the correctness of the calculations and the application of units. Others raise concerns about the interpretation of the wire's dimensions in the context of the calculations.

Discussion Status

The discussion is ongoing, with some participants providing feedback on the original poster's calculations. There is an indication that the answers provided may be incorrect, prompting further exploration of the methodology and assumptions used in the calculations.

Contextual Notes

Participants are working with a past exam question that lacks provided solutions, which may influence their confidence in the correctness of their approaches. There is also a focus on ensuring proper unit usage throughout the calculations.

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Homework Statement



a long straight 6mm diameter conducting wire is carrying a current of 4A.

1)What is the magnitude of the magnetic field at a point 1mm inside the surface of the wire.

2)what is the magnitude of the magnetic field at a point 2cm from the centre of the wire


Homework Equations



using amperes law:
for part 1 i got 44*10^-9

and for part 2: 50*10^-9

I wnt to make sure i have done it right though, because it is a past exam question that i don't have solutions for. So if anyone is good at these questions, it would be helpful to check my answers in case i have stuffed up.


The Attempt at a Solution

 
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The answers to both parts are incorrect.
 
how do you calculate current inside the wire? And do you notice units of all parameters when you calculate?
 
what i tried was:

diameter =6mm. At a point 1mm inside the conducting wire, diameter is 4mm, therefore r=2mm

using amperes law:

∫B⋅ds=μ₀I{Through}

ds=2πr
I{Through}=I∗((πr²)/(πR²)) where R=6mm and r =2mm
B*2πr=I∗((πr²)/(πR²))

B=μ₀Ir/2πR²
B=μ₀(4)(0.002)/2π(0.006)²
 
You wrote diameter = 6mm but then when you put it into eq, you wrote R=6mm.
 
Last edited:

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