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power series of inverse trig functions

 
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Nov12-09, 10:31 PM   #1
 

power series of inverse trig functions


How do you find the power series for inverse trig functions? Can I find the power series for arcsin by manipulating the power series for sin?

Thanks!
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Nov13-09, 07:41 AM   #2
 
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I don't think so.
Even for the simplest of functions you already run into trouble, consider for example y = x2n (for n = 1, 2, ...). The power series for x1/(2n) is already non-trivial.
Nov13-09, 09:04 AM   #3
 
You can, it is called "reversion" of a series. But the formulas get more and more complicated as you proceed.

For arcsin, a better way to find the series is to start with the binomial series for [itex] (1-x^2)^{-1/2}[/itex] and integrate term-by-term.
Nov16-09, 07:37 PM   #4
 

power series of inverse trig functions


Identify the inverse trig function as a hypergeometric function, and manipulate the series expansion of the hypergeometric function. Any book on hypergeometric functions will give the necessary formulae.
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