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power series of inverse trig functions |
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| Nov12-09, 10:31 PM | #1 |
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power series of inverse trig functions
How do you find the power series for inverse trig functions? Can I find the power series for arcsin by manipulating the power series for sin?
Thanks! |
| Nov13-09, 07:41 AM | #2 |
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I don't think so.
Even for the simplest of functions you already run into trouble, consider for example y = x2n (for n = 1, 2, ...). The power series for x1/(2n) is already non-trivial. |
| Nov13-09, 09:04 AM | #3 |
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You can, it is called "reversion" of a series. But the formulas get more and more complicated as you proceed.
For arcsin, a better way to find the series is to start with the binomial series for [itex] (1-x^2)^{-1/2}[/itex] and integrate term-by-term. |
| Nov16-09, 07:37 PM | #4 |
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power series of inverse trig functions
Identify the inverse trig function as a hypergeometric function, and manipulate the series expansion of the hypergeometric function. Any book on hypergeometric functions will give the necessary formulae.
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