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change in entropy at constant temperature |
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| Nov21-09, 12:00 PM | #1 |
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change in entropy at constant temperature
1. The problem statement, all variables and given/known data
Calculate the entropy change when 0.011m3 of a perfect gas at a constant temperature of 273K is compressed from an initial pressure 1x10^5 N/m/m to a pressure of 1x10^6 N/m/m. I know the equation but cannot work out Q!! Please help! 2. Relevant equations dS=Q/T 3. The attempt at a solution |
| Nov21-09, 12:57 PM | #2 |
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Hi ricof, welcome to PF. Can you combine the First Law with what you know about the energy of an ideal gas at constant temperature?
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| Nov21-09, 02:21 PM | #3 |
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Some more relevant equations.
The first law [tex]\Delta E=Q+W[/tex] Work for isothermal expansion [tex]W=-nRTln\frac{V_{f}}{V_{i}}[/tex] If you combine this with what you know about change in internal energy at constant temperature, like Mapes said, and that integral of yours, you can figure out the answer. |
| Nov21-09, 03:48 PM | #4 |
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change in entropy at constant temperature
Because T is constant, there is no change in internal energy right?
And also, in the above equation for isothermal expansion, how is n calculated? |
| Nov21-09, 05:27 PM | #5 |
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| Nov21-09, 08:08 PM | #6 |
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Ok, so as dE = 0,
Q = -W and as PV = nRT, -W=PV ln (v1/v2) which is Q Thanks guys, my answer is correct. Thanks for helping! |
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