Can a Physical Law Formulated by One component Tensor ?

Click For Summary
SUMMARY

The discussion focuses on the formulation of physical laws using tensors, specifically analyzing the number of components based on tensor rank and dimension. It establishes that for scalar tensors (rank 0), there is always one component regardless of dimension, while for vector tensors (rank 1), the number of components equals the dimension. The analysis extends to higher ranks, concluding that in one-dimensional space, physical laws can represent tensors of any rank without requiring a coordinate transformation. This implies that electromagnetism and gravity, both represented in one dimension, possess the same number of components.

PREREQUISITES
  • Understanding of tensor mathematics and ranks
  • Familiarity with scalar and vector concepts
  • Basic knowledge of physical laws in physics
  • Comprehension of dimensional analysis
NEXT STEPS
  • Explore the implications of tensor rank in theoretical physics
  • Study the applications of one-dimensional tensors in electromagnetism
  • Investigate the relationship between tensor components and physical laws
  • Learn about higher-dimensional tensors and their transformations
USEFUL FOR

Physicists, mathematicians, and students interested in advanced theoretical physics, particularly those studying the mathematical foundations of physical laws and tensor analysis.

Antonio Lao
Messages
1,436
Reaction score
1
Can a Physical Law Formulated by One component Tensor ?

The number of component of a tensor of any rank is given by

[tex]c = d^r[/tex]

where c is the number of component, d is the dimension of the tensor, r is the rank of the tensor.

For r=0, the tensors are the scalars. For r=1, the tensors are the vectors.

For r=0
[tex]0^0 = 1[/tex]
[tex]1^0 = 1[/tex]
[tex]2^0 = 1[/tex]
[tex]3^0 = 1[/tex]
[tex]4^0 = 1[/tex]
the above show that for scalar tensors, there is only one component for any dimension. And for scalar tensors even the zero dimension has one component.

For r=1
[tex]0^1 = 0[/tex]
[tex]1^1 = 1[/tex]
[tex]2^1 = 2[/tex]
[tex]3^1 = 3[/tex]
[tex]4^1 = 4[/tex]
the above show that for vector tensors, the number of component is the same as the dimension.

For r=2
[tex]0^2 = 0[/tex]
[tex]1^2 = 1[/tex]
[tex]2^2 = 4[/tex]
[tex]3^2 = 9[/tex]
[tex]4^2 = 16[/tex]

For r=3
[tex]0^3 = 0[/tex]
[tex]1^3 = 1[/tex]
[tex]2^3 = 8[/tex]
[tex]3^3 = 27[/tex]
[tex]4^3 = 64[/tex]

For r=4
[tex]0^4 = 0[/tex]
[tex]1^4 = 1[/tex]
[tex]2^4 = 16[/tex]
[tex]3^4 = 81[/tex]
[tex]4^4 = 256[/tex]

From these, it can be noted that only in 1D is the number of component equals 1 for any tensor. So when a physical law is formulated in one dimension, it can represent tensor of any rank and no transformation is needed hence a coordinate system is not necessary.
 
Last edited:
Physics news on Phys.org
Electromagnetism (rank 1) and gravity (rank 2)would be equal in 1D.
 
That's right. They have the same number of component.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K