# Finding the area of a region between curve and horizontal axis

by Razael
Tags: axis, curve, horizontal, region
 P: 32 1. The problem statement, all variables and given/known data Find the area under y = 6x3 - 2 for 5 <_ x <_ 10 2. Relevant equations 3. The attempt at a solution I'm not sure how it wants us to do it; do we use sigma notation or the general right/left-hand sums? Using sigma notation, delta T = 10-5/n T0= 5/n (?) T1= 10/n Ti = 5i/n 5/n$$\sum6(5i/n)^3 -2$$ 750/n^4 -2 (Sigma) i^3 I'm not sure if I can bring the 2 out like that, and I'm also not sure what i^3 equals (is it (n(n+1)/2)^3?)
 P: 32 Looking back, a T0 of 5 does make a lot more sense. T1, then, would be 5 +5/n, T2 would be 5+10/n, so Ti would be 5+5i/n? 5/n$$\sum6(5+5i/n)^3-2$$ I've started simplifying this and it doesn't look right.