Solving Moon Gravity Problem: 16.2 x 10^-13 N/kg

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Discussion Overview

The discussion revolves around a problem related to calculating the gravitational acceleration on the Moon using the formula for gravitational force. Participants are attempting to simplify the expression and clarify the steps involved in the calculation, including unit analysis and handling of exponents.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents a calculation involving gravitational force using the formula and expresses confusion about the simplification process.
  • Another participant questions the clarity of the initial post and asks for the specific question being addressed, suggesting the use of a calculator for accuracy.
  • A participant clarifies that the problem is taken directly from a test and emphasizes the need to simplify the expression while providing units.
  • One participant provides a numerical result of 1.62 N/kg and discusses the importance of significant figures in the context of the calculation.
  • Another participant suggests that the simplification should focus on the expression involving the gravitational constant and the mass of the Moon divided by the square of the distance, pointing out a potential error in handling the exponents.
  • A participant reiterates the original calculation and identifies an error in exponent handling, indicating the need for careful management of the powers of ten.
  • Another participant notes that the initial approach was correct but that there was an error in the subsequent steps regarding exponent subtraction.

Areas of Agreement / Disagreement

Participants express differing views on the correctness of the calculations and the clarity of the initial post. There is no consensus on the final answer, and multiple interpretations of the steps involved remain evident.

Contextual Notes

Some participants highlight potential issues with formatting and clarity in the presentation of mathematical expressions, which may contribute to misunderstandings in the calculations.

terpsgirl
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(6.67 x 10 ^-11 N m^2/kg^2) (7.36 x 10^22 kg)
___________________________________________
(1.74 x 10^6m) ^2

simplify:

6.67 x 7.36
___________ x 10^-11=22-6(2) x Nm^2/kg^2 * kg
1.74 ^2 ____________ _____________
(10^6)^2 m^2

16.2 x 1 x 10 ^-13 n/kg



What am I doing wrong??
 
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Have a look at what you wrote, it's impossible to read. Moreover, I have no idea what you're doing, and why. What is the actual question you're trying to answer? Is this simply an error in your computation? If so, I suggest you use a calculator.
 
This problem was given on a previous test...the problem is written exactly as seen on the actual exam:

Moons gravity is (6.67 x 10 ^-11 N m^2/kg^2) (7.36 x 10^22 kg)
___________________________________________
(1.74 x 10^6m) ^2


I was to simplify and give units...I ended up w/ an incorrect answer and I did all the steps...
 
1.62 N/kg

Look at the dimensions, you'll see that it ends up being N/kg. Use a calculator, and you'll get a number like:

1.6214559386973180076628352490421

Only keep 3 significant digits and you'll get what I got. Were you allowed to use a calculator? If so, I don't see what was so hard. If not, the question is ridiculous.
 
I think we're supposed to comment on:

[tex]\frac{(6.67 * 10^{-11})*(7.36*10^{22})}{(1.74*10^{6})^2}[/tex]

and its simplification to, hopefully, whatever the result of (6.67*7.36)/(1.74)^2 is times 10^{-1}
you appear to have used the 10^{6} in the denominator twice.
note you can't assume that what you type in the white box will come out the same in the finished article; fixed width fonts anyone? plus all spaces are treated equally, I think. click on the pretty tex to see how to do it
 
terpsgirl said:
16.2 x 1 x 10 ^-13 n/kg

What am I doing wrong??
You handled the exponents incorrectly:
[itex]10^{-11} * 10^{22} / (10^6* 10^6) = 10^{(22-11)}/10^{12} = 10^{11}*10^{-12} = 10^{-1}[/itex].
 
Specifically, you started off good, then did too much of a good thing.

You started off with 10^ [-11+22-6(2)], which is the right way to handle the exponents ( I think, assuming you meant + instead of =).

Then you subtracted the exponents in the denominator again.
 

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