# A question about constant velocity/constant acceleration graphs?

 P: 23 Hey! For a lab, I have to make a few graphs, I just need some clarification. Please correct me if I'm wrong. For a D-T graph, where velocity is constant, the line will be straight. (Diagonal.) For a V-T graph, where velocity is constant, the line will be straight. (Horizontal) ^ Confused about this though, at point 0 what will the y value be? (For example, if the velocity is 3m/s) For a A-T graph, where velocity is constant, there will be NO line. (No acceleration) For a D-T graph, where acceleration is constant, the line will be curved. For a V-T graph, where acceleration is constant, the line will be straight. (Diagonal) For a A-T graph, where acceleration is constant, the line will be straight. (Horizontal)?? ^ For this one I am also confused. I just need to know if I'm on the right track! Ones in bold are the one I'm not sure are correct. Thank you very much for reading! I appreciate any help that is offered. =)
P: 648
 Quote by SoConfused__ Hey! For a lab, I have to make a few graphs, I just need some clarification. Please correct me if I'm wrong. For a D-T graph, where velocity is constant, the line will be straight. (Diagonal.) For a V-T graph, where velocity is constant, the line will be straight. (Horizontal) ^ Confused about this though, at point 0 what will the y value be? (For example, if the velocity is 3m/s)
The horizontal line will be above the horizontal axis at a distance equal to 3m/s on the scale.
 For a A-T graph, where velocity is constant, there will be NO line. (No acceleration)
The line will be horizontal and along the axis where a=0.
 For a D-T graph, where acceleration is constant, the line will be curved. For a V-T graph, where acceleration is constant, the line will be straight. (Diagonal) For a A-T graph, where acceleration is constant, the line will be straight. (Horizontal)?? ^ For this one I am also confused.
The horizontal line will be above the x axis for positive acceleration and below it for negative acceleration.
You are on the right track.

This might help
http://www.bbc.co.uk/scotland/learni...ion_rev1.shtml
 P: 23 thank you for all your help :)

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