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Amplitude of the induced voltage across the coil 
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Mar3010, 10:02 PM

P: 8

If anyone can advise that would be great.
1. The plane of a 5 turn coil of 5mm² cross sectional area is rotating a 1200 r.p.m in a magnetic field of 10mT. Q. Calculate the amplitude of the induced voltage across the coil Data: 5 turns c = 1200 rpm A = 5cm² B = 10 mT 2. φ = N.B.A φ = 5×10×10^3 ×5 × 10^2 φ = 2.5 ×10^3 V = dφ/dt or N.A. dB/dt The equation thought to have been used is the following but the Length is not vissible to me. V/L = c x B c being the speed B field L lenth of wire 3. I have tried two avenues please advise a: V(t) = N•d(B•A)/dt = N•B•dA/dt = N•B•ω•A•sin(ωt) V(t) =(5)(10x10^3)(125.66370599999999)(5)sin(ωt) = 31.415 sin(ωt) volts. Or b: And using the following, saying t = 60 sec Then φ = N.B.A φ = 5×10×10^3 ×5 × 10^2 φ = 2.5 ×10^3 And V = dφ/dt or N.A. dB/dt = 4.17x10^3 V My concern here is that 1200rpm was not used. 


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