Find the maximum amplitude of the induced EMF

In summary, the amplitude of the induced emf in a 12 turn coil with area A = ##90cm^{2}## at the receiver is 4.6x10^{-3}V.
  • #1
chocolatecake
16
4

Homework Statement


[/B]
A radio transmitter radiates isotropically at the frequency of 90.8 MHz. The peak magnetic field at
a receiver, 9km from the transmitter, is ##9x10^{-10}T##. Calculate the maximum amplitude of the induced emf in a 12 turn coil with area A = ##90cm^{2}## at the receiver. Hint: choose the optimal angle.

Homework Equations



The amplitude of induced emf: ##ε=BAω##
##ε=-N\frac{dΦ}{dt}=-NABωcos(ωt)##
##Φ=NBA##
##Φ=NABsin(ωt)##
##Φ=BAcosθ##
All the equations for Φ are in the lecture slides but how can I know which one is the correct one? Why are there several equations for Φ?

The Attempt at a Solution



First, I thought I have to find the first derivative etc. to find the absolute maximum since the question is asking about the maximum amplitude. But in one of the lectures we had a similar example (the question was to find the amplitude of the electromotive force induced in the loop by the signal. And the numbers were different, of course). In the example, they used this equation: ##ε=BAω##
If I use the same equation for my problem, I get this:
##ω=(2)(π)(f)##
##ω=(2)(π)(9.08x10^7Hz)=5.7x10^8rad/s##
Plug in:
##ε=BAω##
##ε=(9x10^{-10}T)(0.009m^2)(5.7x10^8rad/s)##
##ε=4.6x10^{-3}V##

However, since the problem includes the hint about the angle, and my solution doesn't include an angle, I'm guessing that my solution is wrong. So how should I approach the problem instead? Any help is much appreciated!
Many thanks! :)
 
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  • #2
chocolatecake said:
Plug in:
##
ε=BAω##
This is what you should use
##ε=-N\frac{dΦ}{dt}=-NABωcos(ωt)##
What happened to ##N##? What happened to ##\cos(\omega t)##?
 
  • #3
Ok, but why do I have to use this equation?
 
  • #4
Another problem is, is that t is not given, so I can't really solve the equation.
 
  • #5
chocolatecake said:
Ok, but why do I have to use this equation?
It's called Faraday's law (one of the Maxwell equations thta govern electromagnetism).

chocolatecake said:
Another problem is, is that t is not given, so I can't really solve the equation.
You don't have to. Check the definition of amplitude.
 
  • #6
chocolatecake said:
my solution doesn't include an angle
In the last of your equations there is a factor ##\cos\theta## that you can optimize.

Do you understand your own relevant formulas ? If not, you have to go back to where they come from and find out what the variables are and what the equation describes.
 
  • #7
BvU said:
You don't have to. Check the definition of amplitude.
Is the amplitude is the maximum displacement in the y direction? So I have to find the derivative?

BvU said:
It's called Faraday's law (one of the Maxwell equations thta govern electromagnetism).
That I do understand, but I found many different equations for Φ and I don't know which one is the correct one. For example, here it says that ##Φ=NBAcosθ## , on this website ##Φ=NBA## and according to our professor ##Φ=NABsin(ωt)##. I don't think that my professor is wrong but I don't understand why there are so many different equations for the same thing. Since there are so many, can they be used interchangeably?
 
  • #8
BvU said:
If not, you have to go back to where they come from and find out what the variables are and what the equation describes.
Well N is the number of turns, Φ is the magnetic flux, B is the magnetic field and A the area.
 
  • #9
And ω is the angular frequency in rad/s
 
  • #10
chocolatecake said:
The amplitude of induced emf:
  1. ##\varepsilon =BA\omega ##
  2. ##\varepsilon =−N\displaystyle {d\Phi\over dt} =−NAB\omega \cos(\omega t) ##
  3. ##\Phi =NBA ##
  4. ##\Phi =NAB\sin (\omega t) ##
  5. ##\Phi =BA\cos\theta##
All the equations for Φ are in the lecture slides but how can I know which one is the correct one?
Why are there several equations for Φ?

They are all one and the same relationship:
  1. Is for the amplitude of ##\varepsilon## in a rotating one turn loop OR a loop in a time-dependent B(t) = |B| ##\cos(\omega t##)
  2. Is for ##\varepsilon(t)## of a rotating N turn coil OR a fixed coil with a time-dependent B = |B| ##\cos(\omega t)##
  3. Is a flux -- can be time dependent if B is time dependent or the coil rotates
  4. Is 3 if the coil rotates OR the B as in 2
  5. has a ##\theta## for the orientation of the coil.
Once you understand the material you won't have a problem picking the right expression.
 

1. What does "maximum amplitude" refer to in the context of induced EMF?

The maximum amplitude of the induced EMF refers to the highest value or peak of the induced electromotive force. It is the highest point on the graph of the induced EMF over time.

2. How is the maximum amplitude of induced EMF calculated?

The maximum amplitude of induced EMF can be calculated using the formula E = -N(dΦ/dt), where E is the induced electromotive force, N is the number of turns in the coil, and (dΦ/dt) is the rate of change of magnetic flux over time.

3. Why is it important to find the maximum amplitude of induced EMF?

Knowing the maximum amplitude of induced EMF is important because it helps in understanding the strength of the induced current and the behavior of the electromagnetic system. It also helps in designing and optimizing devices that use electromagnetic induction, such as generators and transformers.

4. How does the strength of the magnetic field affect the maximum amplitude of induced EMF?

The strength of the magnetic field is directly proportional to the maximum amplitude of induced EMF. This means that a stronger magnetic field will result in a higher maximum amplitude of induced EMF.

5. Can the maximum amplitude of induced EMF be negative?

Yes, the maximum amplitude of induced EMF can be negative. This occurs when the rate of change of magnetic flux is decreasing, resulting in an induced EMF that opposes the change in the magnetic field. This is known as Lenz's Law and is an important principle in electromagnetic induction.

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