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Qn on Rotational Kinetic Energy |
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| Mar31-10, 09:52 PM | #1 |
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Qn on Rotational Kinetic Energy
1. The problem statement, all variables and given/known data
Crab Nebula releases energy at a rate of 5x1031 W, obtaining its energy from the rotational kinetic energy K of a neutron star at its centre. Period of neutron star's rotation = 0.0331s. T increases by 4.22 x 10-13s per second. What is the moment of inertia of the neutron star? 2. Relevant equations dK/dt = -(4[tex]\pi[/tex]2I/T3) (dT/dt) This was the first part of the question which I managed to prove already. *Note: the pi is not supposed to be in superscript. 3. The attempt at a solution I equated the power of the star to the above differential equation. Solving for I should be quite easy, but somehow my answer (1.1x 1038) is different from the answer provided (1.1 x 1030). |
| Apr1-10, 02:18 AM | #2 |
Recognitions:
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Your result looks correct.
ehild |
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