## sum of real numbers

1. The problem statement, all variables and given/known data
if the real numbers x,y,z,w satisfy (x2/(n2-1))+(y2/(n2-32))+(z2/(n2-52))+(w2/(n2-72)) for n=2,4,6,8 then prove
x2+y2+z2+w2=36

2. Relevant equations

3. The attempt at a solution
unable to think of anything???
 Recognitions: Homework Help Unless I'm missing something, the problem you posted isn't consistent - what do your numbers x, y, z, w satisfy?

 Quote by radou Unless I'm missing something, the problem you posted isn't consistent - what do your numbers x, y, z, w satisfy?

sorry the exact equation is as follows
[(x2/(n2-1))+(y2/(n2-32))+(z2/(n2-52))+(w2/(n2-72))]=1

## sum of real numbers

plz help

Mentor
Edit: Add "= 1" to make an equation below.
 Quote by jeedoubts 1. The problem statement, all variables and given/known data if the real numbers x,y,z,w satisfy (x2/(n2-1))+(y2/(n2-32))+(z2/(n2-52))+(w2/(n2-72)) = 1 for n=2,4,6,8 then prove x2+y2+z2+w2=36 2. Relevant equations 3. The attempt at a solution unable to think of anything???
You're unable to think of anything? The most obvious starting point is substituting n = 2, n = 4, n = 6, and n = 8, and seeing what you get.

Mentor
 Quote by Mark44 Edit: Add "= 1" to make an equation below. You're unable to think of anything? The most obvious starting point is substituting n = 2, n = 4, n = 6, and n = 8, and seeing what you get.
That will give you four different equations in four unknowns -- in other words, exactly what is needed to solve the problem.