Prove that the equation is satisfied at least once

  • Thread starter giokrutoi
  • Start date
We know that f(n) outputs the smallest integer greater than n^pi, so we can use this to show that there exists a natural number x0 that satisfies the equation. By the well ordering principle, there exists a smallest x0 that satisfies the equation. We can then use induction to show that there exists a natural number x1 that satisfies the equation, and continue this process until we have a sequence of natural numbers abcdwxyz that all satisfy the equation and are not smaller than 2015. Therefore, we have proven that there exists natural numbers abcdwxyz that are all not smaller than 2015 and satisfy the equation f(x) + f(y) + f(z) + f(w) = f(a) +
  • #1
giokrutoi
128
1

Homework Statement


f(n) is function that takes input n and outputs the smallest integer grater that n^pi
prove that there exists natural numbers abcdwxyz that are all not smaller than 2015 such that equation is satisfied
f(x) + f(y) + f(z) + f(w) = f(a) + f(b) + f(c) + f(d)
and they abcd and wxyz are not trivial meaning that a,b,c,d is not equal to w,x,y,z

Homework Equations



well ordering principal
or maybe induction

The Attempt at a Solution


f(x) + f(y) + f(z) + f(w) = f(a) + f(b) + f(c) + f(d)
f(x) = [x^pi + 1]
f(y) = [y^pi + 1]
and so on
[x] means greatest number smaller than x for example [32.23] = 32 [12.99] = 12
let x0 be the smallest x that satisfies the equation
and i am stuck i don't know what to do afterwards
 
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  • #2
The pigeonhole principle can help here.
 

1. How do you prove that an equation is satisfied at least once?

To prove that an equation is satisfied at least once, you can use methods such as substitution, graphing, or algebraic manipulation. By substituting values for the variables in the equation and solving for the unknowns, you can determine if there is a solution. Similarly, graphing the equation can show where it intersects with the x and y axes, indicating solutions. Lastly, you can manipulate the equation algebraically to show that it can be satisfied by at least one solution.

2. What does it mean for an equation to be satisfied at least once?

When an equation is satisfied at least once, it means that there is at least one set of values for the variables that make the equation true. In other words, there exists a solution or solutions that satisfy the equation.

3. Can an equation be satisfied more than once?

Yes, an equation can be satisfied more than once. This means that there are multiple sets of values for the variables that make the equation true. These solutions can be represented as points on a graph where the equation intersects with the x and y axes.

4. Why is it important to prove that an equation is satisfied at least once?

Proving that an equation is satisfied at least once is important because it verifies the validity of the equation. It also allows us to find solutions to the equation, which can have practical applications in various fields, such as engineering, physics, and economics.

5. What happens if an equation cannot be satisfied?

If an equation cannot be satisfied, it means that there are no values for the variables that make the equation true. This could indicate that the equation is invalid or that there is no solution to the problem being represented by the equation. In some cases, it could also mean that there is a mistake in the equation or that it is missing crucial information.

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