# I need help in partioning bits of random number in matlab

by absolute76
Tags: bits, matlab, number, partioning, random
 P: 21 Hey guys, I really need your help here...What i wanted to do actually is to partition the bits into 4 smaller group.. If anyone of you can give me a basic coding of it or maybe u can check if there anything wrong wit my coding.. Ex: x=80 rand('state',100) randn('state',200) a=rand(1,x)>0.5 should i do for loop? should i add this function Ex: for x=(4:1:4) a=rand(1,x)>0.5 end but it will not give me a random number 0f 4 bits..how??? anyone can helpp please??
Mentor
P: 21,397
 Quote by absolute76 Hey guys, I really need your help here...What i wanted to do actually is to partition the bits into 4 smaller group..
I don't understand what you're saying.
 Quote by absolute76 If anyone of you can give me a basic coding of it or maybe u can check if there anything wrong wit my coding.. Ex: x=80 rand('state',100) randn('state',200) a=rand(1,x)>0.5 should i do for loop? should i add this function Ex: for x=(4:1:4) a=rand(1,x)>0.5 end but it will not give me a random number 0f 4 bits..how??? anyone can helpp please??
Can you tell me in words what you're trying to do? Here is some documentation for the randn function - http://www.mathworks.com/access/help...ref/randn.html

and for the rand function - http://www.mathworks.com/access/help.../ref/rand.html

If you need a loop it should look something like this.
do i=1:2:9
% some calculation
end
This loop runs 5 times, for i = 1, 3, 5, 7, and 9.
 P: 21 Ok, let say i have 40 bits.. My question now is..how do i do 5 partition for the 40 bits (each partition consists of 8 bits)so that everytime i simulate it,it will randomly pick 8 bits from the 40 bits?? but i have to use this code in it: x=40 rand('state',100); randn('state',200); input=rand(1,x)>0.5 do you have any idea??
 Mentor P: 21,397 I need help in partioning bits of random number in matlab I don't think partitioning the set of bits enters into it. And your explanation is still not very clear. My best guess is that you have 40 bits to choose from, with indexes in the set {0, 1, 2, 3, 4, ..., 38, 39} and you want to pick 8 bits at random. The following statement will store an integer from 0 through 39 in x. If you do that 8 times, you'll get 8 different values. x = fix(40 * rand) This code will put 8 values in an array. do i = 1:8 x(i) = fix(40 * rand) end
P: 21
 Quote by Mark44 I don't think partitioning the set of bits enters into it. And your explanation is still not very clear. My best guess is that you have 40 bits to choose from, with indexes in the set {0, 1, 2, 3, 4, ..., 38, 39} and you want to pick 8 bits at random. The following statement will store an integer from 0 through 39 in x. If you do that 8 times, you'll get 8 different values. x = fix(40 * rand) This code will put 8 values in an array. do i = 1:8 x(i) = fix(40 * rand) end
Ok that's true i have 40 bits now.

and because of :

rand('state',100);
randn('state',200);
a=rand(1,x)>0.5 .......this line will generate 0,1 with equal probility

so my 40 bits just now are being generated as 0 and 1

and through that i want to partition it into 5 section( each of it will consist of 8 bits). The 8 bits will be choose randomly from the output I've given.

Example of evaluate of that selection i have this output:

x =

40

a =

Columns 1 through 14

0 1 1 1 1 1 1 0 0 1 1 1 0 0

Columns 15 through 28

1 0 1 0 0 0 1 1 1 0 1 0 1 1

Columns 29 through 40

1 1 0 0 1 1 1 0 1 0 0 1

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