# Radius of Fermi Sphere

by misterpickle
Tags: fermi, radius, sphere
 P: 12 1. The problem statement, all variables and given/known data Problem 9.2(B) from Kittel Solid State Physics. A two-dimensional metal has one atom of valence one in a simple rectangular primitive cell of a1 = 2Å and a2 = 4Å. Calculate the radius of the free electron Fermi sphere and draw this sphere to scale on the drawing of the Brillouin zones. A 2D solution that seems to be correct is posted here . Can anyone tell me what is wrong with my approach? Also, some equations weren't working for the latex. Sorry. 3. The attempt at a solution First I find the electron concentration in terms of $k_{F}[\latex] [latex]V=(4/3) \pi k^{3}$ $N=2*(4/3)*\frac{\pi k^{3}}{V_{k}}$ where V_{k}=\frac{2 \pi}{a}*\frac{2 \pi}{a}*\frac{2 \pi}{b}=\frac{4 \pi^{3}}{a^{3}} (latex code didn't work for this) which is the k-space volume. The factor of 2 is the electron spin degeneracy. The electron concentration, N, is then: $N=\frac{8}{3}\frac{\pi k^{3}a^{3}}{4\pi^{3}}=\frac{2k^{3}a^{3}}{3\pi^{2}}$ which gives $k=(\frac{3\pi^{2}N}{2a^{3}})^{1/3}$ using N=1 and plugging in the values for a and b I get. k=(3\pi^{2})/16 (the latex code is screwing up for some reason) This gives me 1.23 A^-1. Where did I go wrong?
 P: 676 Why is your momentum space 3d when the problem is 2d?

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