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Finding Equivalence Class |
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| May3-10, 07:06 AM | #1 |
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Finding Equivalence Class
1. The problem statement, all variables and given/known data
Find the equivalence class [2] for the following equivalence relations: a) R: Z <-> Z, where xRy, iff |x| = |y| b) T: N <-> N, where xTy, iff xmod4 = ymod4 N means natural numbers etc...there wasnt the correct symbols in the latex reference 2. Relevant equations ?? 3. The attempt at a solution Ok so I know how to do the b) part, because we had examples at the class, its: [0] = {0,4,8,12,...} [1] = {1,5,9,13,...} [2] = {2,6,10,14,...} so the answer is [2] = {2,6,10,14,...} right? but i dont know how i start to build it when i have |x| = |y| its probably something very easy and i just dont get it for some reason |
| May3-10, 07:11 AM | #2 |
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Suppose x is given but unknown, and that |x| = |y|. What can y equal in terms of the given x?
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| May3-10, 07:33 AM | #3 |
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hmmm...y must always be +x or -x?
but i dont understand how the classes are formed. For example class [0], does it mean the list starts at 0? In the b-part the list increases always by 4, but what about in this, by 1? |
| May3-10, 07:38 AM | #4 |
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Finding Equivalence Class
Now think about concrete examples. If x = -3, what can y be? Consequently, what is [-3]?
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| May3-10, 07:50 AM | #5 |
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if x = -3, then y can then be 3 or -3
What is [-3]? I dont know, {..., ???, -3, ???, ...} |
| May3-10, 07:59 AM | #6 |
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Do you understand why the answer to b) is the answer to b)? Back to a).
[x] = {y | xRy} = {y in Z | |y| = |x|} [-3] = {y | (-3)Ry} = {y in Z | |y| = |-3|} |
| May3-10, 08:27 AM | #7 |
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| May3-10, 08:39 AM | #8 |
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I thought I understood the b) part, but now im not sure if i do deeply enough.
So, in each class the elements are "equivalent" in the way the equivalence relation is defined? xmod4 = ymod4 means every element which has same modulus when divided by 4 belong to same class? can [-3] then be only {-3,3} in the a) -part? And [-2] = {-2,2} etc? I'm confused because we only had those modulus examples in the class and in book and I dont think I understood the theory deeply enough =) |
| May3-10, 09:01 AM | #9 |
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![]() What about [0] in a)? |
| May3-10, 09:12 AM | #10 |
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[0] must then be only {0}
What about R: R <-> R, where xRy, iff floor(x) = floor(y) i dont know if floor() is the right way to write floor function, but cant find the correct symbol. [2] is then something like {2, 2.1, 2.2, ... , 2.99999...} but what is the correct way to write it? Because 2 can have any amount of decimals after it. Does it have to be in a list form like a) and b) here was? Thanks much for the replies, you helped me alot! |
| May3-10, 09:20 AM | #11 |
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| May7-10, 01:21 PM | #12 |
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