Register to reply

Work done on a block

by thereddevils
Tags: block, work
Share this thread:
thereddevils
#1
May30-10, 04:38 AM
P: 439
1. The problem statement, all variables and given/known data

A wooden block of mass 1.2 kg with dimensions 20cm x 10 cm x 10cm . It's resting on the surface PQYX (with base area 10cm x 10 cm , the vertical side would be 20cm in this case).What is the work done to enable it to rest on surface PQYX

2. Relevant equations



3. The attempt at a solution

On first thought , work done is simply the gain in potential energy ,

mgh=(1.2)(10)(0.2)=2.4 J

but that isn't the answer .
Phys.Org News Partner Science news on Phys.org
Wearable 4MM jetpack tested on speed, agility for runners (w/ Video)
How did evolution optimize circadian clocks?
Corn spots: Study finds important genes in defense response
tomwilliam
#2
May30-10, 04:50 AM
P: 128
In my understanding, there is no work done if the box is not moving.
You can say that the forces are balanced... that the frictional force acting up the slope is equal in magnitude to the component of the box's weight pointing down the slope, but as Work = (Force) x (distance in direction of the force), my understanding is that no work is done if the box remains steady.
tiny-tim
#3
May30-10, 04:52 AM
Sci Advisor
HW Helper
Thanks
tiny-tim's Avatar
P: 26,148
Hi thereddevils!
Quote Quote by thereddevils View Post
A wooden block of mass 1.2 kg with dimensions 20cm x 10 cm x 10cm . It's resting on the surface PQYX (with base area 10cm x 10 cm , the vertical side would be 20cm in this case).What is the work done to enable it to rest on surface PQYX
I don't understand

is the block tilted?

and where is the block moving from and to?

thereddevils
#4
May30-10, 04:57 AM
P: 439
Work done on a block

Quote Quote by tiny-tim View Post
Hi thereddevils!


I don't understand

is the block tilted?

and where is the block moving from and to?
sorry , i should hv posted the complete question.

Figure 23 shows a wooden block of mass 1.2 kg with dimensions 20cm x 10 cm x 10cm . It's resting on the surface PQRS . What is the workdone to enable it to rest on the surface PQYX ?

PQRS is of base area (20 x 10) and PQXY (10 x10)

THe block is neither moving nor its tilted .
tiny-tim
#5
May30-10, 05:05 AM
Sci Advisor
HW Helper
Thanks
tiny-tim's Avatar
P: 26,148
Well, work done is force "dot" displacement

if nothing has moved, then what's the displacement?


Register to reply

Related Discussions
Block and spring collision - work Introductory Physics Homework 2
Work done on a block by net force Introductory Physics Homework 4
Work done on the block by force Introductory Physics Homework 5
Block on incline: work Introductory Physics Homework 2
Work on a sliding Block Introductory Physics Homework 9