Ohm's Law: Voltage Across Ideal Wire = 0

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Discussion Overview

The discussion revolves around the interpretation of Ohm's Law in the context of an ideal wire with zero resistance and its implications for voltage across the wire in a circuit. Participants explore theoretical aspects of electrical circuits, specifically addressing the concept of voltage in ideal conditions versus real-world scenarios.

Discussion Character

  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions the statement that there is no voltage across an ideal wire, expressing confusion about the potential difference between points connected by the wire and the battery.
  • Another participant asserts that there is no ideal voltage source, suggesting that in practical scenarios, voltage drops when current increases, challenging the idealized conditions discussed.
  • A different participant acknowledges the idealized nature of the wire and voltage source but seeks clarity on how Ohm's Law applies in this context.
  • One reply emphasizes the unrealistic nature of ideal components, questioning the relevance of contemplating such scenarios.
  • Another participant references Maxwell's equations to support the argument against the existence of ideal components in practical applications.

Areas of Agreement / Disagreement

Participants express differing views on the existence and relevance of ideal components in electrical circuits. There is no consensus on the interpretation of voltage across an ideal wire, and the discussion remains unresolved.

Contextual Notes

Participants highlight limitations in applying theoretical concepts to real-world scenarios, noting the dependence on idealized definitions and the complexities introduced by practical components.

cepheid
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Now, this question may be incredibly stupid, but it has been bothering me nonetheless. Say you have a basic circuit loop as shown in the picture.

Ohm's law:

[tex]V = RI[/tex]

Now, according to a textbook I'm reading right now, "By Ohm's law, there is no voltage across an ideal (i.e. zero-resistance) wire regardless of the current flowing through it."

I'm just wondering what the meaning of that statement is. Yeah, sure, obviously:

[tex]V = 0I = 0[/tex]

But when I look at that picture, here's how I see it: there is definitely a potential difference between points A and B, because they are at either end of the battery. But these points are also the two ends of the wire that makes up the loop! So how could there possibly not be a potential difference across the wire?! And if there weren't, why would there be any current at all? Aren't the electrons moving from a point of high potential to low potential, gaining KE along the way?
 

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There is no ideal voltage source. Meaning that for any realistic source, as current demanded is increased, you'll reach a point where voltage will start to drop. You can try this. put a voltmeter across a battery. Now short it out. I guarantee that if the shorting wire does not melt into a puddle, the voltage reading will drop to zero.
 
Hmm...

I've seen someone (inadvertantly) short a battery in the lab, using one of those dinky jumper wires. The wire was toast...went up in an impressive display of pyrotechnics. Unfortunately, this explanation doesn't make the answer to my question clear to me. My fault. Maybe the problem is that my question is sillier than you were expecting. I'm asking about the idealised, perfectly conducting wire referred to in the textbook quote. You connect the ends of it to the terminals of a battery. So how could there be no voltage across the wire?
 
So you are considering a case of an ideal wire and an ideal voltage source, and worrying that Ohm's law doesn't seem to apply? Do you realize that ideal means unreal? Are you the type of person who wastes time contemplating what happens when an irresistable force is applied to an immovable object?
 
Krab is obviously on summer vacation. There is no such thing as an ideal wire or an ideal voltage source. See the Maxwell equation.
 

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