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analytic functions |
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| Jun3-10, 05:42 PM | #1 |
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analytic functions
1. The problem statement, all variables and given/known data
Let g(z) be an analytic function. I have to show that g'(z) is also analytic, using only the CR eqns. I am given that the 2nd partials are continuous 2. Relevant equations let f(x,y)=u(x,y)+iv(x,y) CR: du/dx=dv/dy and du/dy=-dv/dx continuous 2nd partials: d/dx(du/dy)=d/dy(du/dx) and d/dx(dv/dy)=d/dy(dv/dx) 3. The attempt at a solution I am confused as to how to express the derivative df/dz. would f'=du/dx+du/dy+idv/dx+idv/dy? |
| Jun3-10, 07:43 PM | #2 |
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I don't think you want df/dz. If a function satisfies the CR equations and has continuous partials, what can you say about it?
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| Jun3-10, 09:47 PM | #3 |
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I have to solve this problem using only calculus. I can't use any theorems like using Taylor series. Maybe I can say that it is harmonic?
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| Jun4-10, 08:24 AM | #4 |
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analytic functions
nvm- got it! f'(z)=du/dx+idv/dx. Taking these and the real and imaginary parts, we can get the CR eqns for f' using the CR eqns for f and the fact that the mixed partials are equal.
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