Calculate Grams of Solute Needed for 0.1 N Ca(OH)2 & 5% NaCl

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Homework Help Overview

The discussion revolves around calculating the grams of solute required to prepare specific concentrations of two solutions: a 0.1 N solution of Ca(OH)2 and a 5% solution of NaCl. The subject area includes concepts from chemistry related to normality and percentage concentration.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of grams of solute for a normal solution and raise questions about the formula needed for such calculations. There is also clarification sought regarding the interpretation of percentage concentration in the context of NaCl.

Discussion Status

The discussion is active, with participants sharing their understanding and confusion regarding the calculations. Some guidance has been offered about the nature of normal solutions, but there is no explicit consensus on the methods to be used for the calculations.

Contextual Notes

Participants express uncertainty about the formulas for calculating grams of solute for normal solutions and percentage solutions, indicating a need for foundational understanding in these areas.

buffgilville
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Please help me with this:

Calculate how many grams of solute are necessary to prepare:
1) 100 mL of 0.1 N (Normal Solution) Ca(OH)2 (molecular weight = 74)

2) 100 mL 5% NaCl (molecular weight = 40)
 
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What have you tried so far and where are you getting stuck?
 
I know how to find the solute of Molarity of solution, but I don't know how to find the grams of solute for Normal Solution. I've never done this type of question, and I can't find the formula to find it.

As for question 2, I I know that a solution is 1% when it contains 1 gram of solute per 100 mL of solution. The question is 100mL of 5% NaCl. Does that mean that there is 5 grams of solute? Is there a formula for solving this type of problems?
 
A 0.1 Normal solution contains 0.1 moles of solute per liter of solution.
 

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