commutator of x and p


by lihurricane
Tags: commutator
lihurricane
lihurricane is offline
#1
Sep16-10, 10:06 AM
P: 3
i have met a problem about the commutator of x and p.
[x,p]=ihbar

/p> is the eigenstate of momentum operator p.

<p/xp-px/p>

=<p/xp/p>-<p/px/p>

=p<p/x/p>-p<p/x/p> the second term is got by the momentum operator p acting on
the left state.

=0

so i get zero! is there anyone can point out where i am wrong?
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arkajad
arkajad is offline
#2
Sep16-10, 11:35 AM
P: 1,412
Can you calculate <p|x|p>? Which number will you get? I can tell you: any number you want, depending on how you decide to calculate it. You are playing pseudo-math with formal expressions without really understanding their mathematical meaning. That is how many paradoxes appear.

Many theorems in mathematics are valid under certain assumptions. Skip the assumptions, apply the theorem, and you can well create a paradox.
strangerep
strangerep is offline
#3
Sep16-10, 06:20 PM
Sci Advisor
P: 1,722
Quote Quote by lihurricane View Post
[...]
so i get zero! is there anyone can point out where i am wrong?
Take a look at Post #18 in this (very recent) thread:

http://www.physicsforums.com/showthr...=426509&page=2

More importantly, check out the references I mentioned. :-)

lihurricane
lihurricane is offline
#4
Sep16-10, 10:39 PM
P: 3

commutator of x and p


Quote Quote by strangerep View Post
Take a look at Post #18 in this (very recent) thread:

http://www.physicsforums.com/showthr...=426509&page=2

More importantly, check out the references I mentioned. :-)



Thank you very much! i think it will help me.


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