find current at high/low frequency


by Acuben
Tags: current, frequency, high or low
Acuben
Acuben is offline
#1
Oct3-10, 12:54 AM
P: 61
1. The problem statement, all variables and given/known data
find the rms current delievered by the 45v (rms) power supply when
a) the frequency is very large
and b) the frequency is very small.

answer: a) 225mA, b) 450mA

http://yfrog.com/jucurrentqg



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2. Relevant equations
w= angular velocity (supposed to be omega)
L= inductor
C= capacitor
j= complex coefficent = sqrt(-1)
Zl= resistance of inductor
Zc= resistance of capacitor
Ztot= total resistance
R= resistance of resistor
P= Power

Xl=wL
Xc=1/wc
Zl=j*Xl
Zc=-j*Xc
Ztot= R + Zl + Zc = R + j(Xl-Xc)



3. The attempt at a solution

with frequency just being high, how am I supposed to get these exact numbers without letters/symbol for I? o.o I tried the calculation and omega did not cancel out either.
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zhermes
zhermes is offline
#2
Oct3-10, 02:24 AM
P: 1,262
The key idea is that in the case of very high or very low frequency, you can take the impedance (resistance) of the inductor and capacitor to be ~infinite, respectively. Does it make sense why that's true (as an approximation at least)?

In effect, this eliminates one of the two loops in the circuit for each case.
Acuben
Acuben is offline
#3
Oct4-10, 02:19 PM
P: 61
Quote Quote by zhermes View Post
The key idea is that in the case of very high or very low frequency, you can take the impedance (resistance) of the inductor and capacitor to be ~infinite, respectively. Does it make sense why that's true (as an approximation at least)?

In effect, this eliminates one of the two loops in the circuit for each case.
ah yes it does, at first I thought the resistance would skyrocket to infinity / 0
thank you


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