
#1
Oct410, 02:11 PM

P: 13

1. The problem statement, all variables and given/known data
The average person has 1.4 m^2 of skin at a skin temperature of roughly 306 K. Consider the average person to be an ideal radiator standing in a room at a temperature of 293 K. a.) Calculate the energy per second radiated by the average person in the form of blackbody radiation. Express you answer in watts. (How do I treat the temperature?) 2. Relevant equations L=AσT^4 Where A = area; σ = StefanBoltzmann constant; T = temperature (in Kelvins). 3. The attempt at a solution L=(1.4)*(5.670400*10^8)*(????)^4 



#2
Oct410, 08:54 PM

P: 1,262

The energy per second radiated will just be that equation with body temperature as T (~310 Kelvin); but note that this isn't the same as the total energy lost per second.




#3
Oct2310, 08:20 AM

P: 12

Energy radiated per unit time will be given by StefanBoltzman law 
dQ/dt = eAσT^4 (σ  Stefan's constant) but here 'T' is to be taken in Kelvin and not degree celsius. and also this is not the energy lost since energy lost = (Energy radiated)(Energy absorbed) put T value in the equation. For heat radiated T=306 and for absorbed T=293 


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