Calculating Quanta Emitted by a Blackbody at 500 C

In summary, the temperature of a blackbody is 500 C or 773.15 K. If the intensity of the emitted radiation is 2.0 W/m^2, and this is due entirely to the most intense frequency component, it can be calculated that 3750 nm or 3.75 x 10^-6 m is the maximum wavelength. The total energy radiated per unit time per unit surface area can be determined using the relationship J=∫^{∞}_{0}J_{λ}(T)dλ.
  • #1
Aoiumi
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Homework Statement



The temperature of a blackbody is 500 C. If the intensity of the emitted radiation, 2.0 W/m^2, were due entirely to the most intense frequency component, how many quanta of radiation would be emiteed per second per square meter?

Homework Equations



λmaxT = 2.90 x 10^-3 m K


The Attempt at a Solution



I'm not sure where to begin or how to use intensity.
500 C = 773.15 K

I calculated λmax = 2.90 x 10^-3 m K / 773.15 K = 3750 nm or 3.75 x 10 ^-6 m. I'm not sure where to go from here. Please help. Thank you!
 
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  • #2
A useful relationship to consider is this one:

[itex]J=∫^{∞}_{0}J_{λ}(T)dλ[/itex]

This tells you the total energy radiated per unit time per unit surface area of a black body.
 
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  • #3
Thank you!
 

1. What is blackbody radiation?

Blackbody radiation is the electromagnetic radiation emitted by a perfect blackbody, which is an idealized object that absorbs all electromagnetic radiation incident on it. It is a type of thermal radiation and is emitted by all objects with a temperature above absolute zero.

2. How is blackbody radiation related to temperature?

The intensity and wavelength distribution of blackbody radiation is dependent on the temperature of the object emitting it. As the temperature of the object increases, the intensity of the radiation increases and the peak wavelength shifts to shorter wavelengths.

3. What is the significance of blackbody radiation in physics?

Blackbody radiation is an important concept in physics because it provided early evidence for the existence of quantum mechanics and helped to develop the idea of energy quantization. It is also used in various fields such as astronomy, cosmology, and materials science to study the properties of objects and their temperatures.

4. What is the difference between blackbody radiation and thermal radiation?

Blackbody radiation is a type of thermal radiation that is emitted by a perfect blackbody, while thermal radiation refers to the emission of any type of electromagnetic radiation by an object with a temperature above absolute zero. Blackbody radiation follows a specific intensity and wavelength distribution, while thermal radiation can vary depending on the material and conditions of the object emitting it.

5. How is blackbody radiation measured and observed?

Blackbody radiation can be measured using instruments such as a spectrometer or a pyrometer. It can also be observed visually as the glowing light emitted by hot objects, such as a heated metal rod. Scientists can also study the intensity and wavelength distribution of blackbody radiation by creating a blackbody cavity, which is a chamber with a small opening that allows only certain wavelengths of radiation to escape.

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