Instantaneous velocity expression

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Homework Help Overview

The discussion revolves around finding the instantaneous velocity from a given position function expressed as a polynomial in time. The specific context involves evaluating this expression at a particular time, t=0.000s.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between instantaneous velocity and position, with one suggesting the use of derivatives to find the instantaneous velocity. There is also a question about the correctness of the derived expression for velocity.

Discussion Status

The discussion includes attempts to derive the instantaneous velocity and check the correctness of the derivative. Some participants express uncertainty about their calculations and the use of variables, indicating a collaborative exploration of the topic.

Contextual Notes

There are indications of confusion regarding variable notation and the presentation of equations, as well as a mention of learning and practice in the context of the discussion.

UrbanXrisis
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This is an equation of a position v time graph:

x=342t^4-127t^3+1.87t^2+2.45t

I need to use this expression to find the instantaneous velocity at t=0.000s
 
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And how is inst. velocity related to position?
 
take the derivative of the first equation
then just plug in t
and volla you got instantious velocity
 
Last edited:
x`=1368t^3-381t^2+3.74t+2.45

is that correct?
 
When you are done check your answer

This is what i got
its in white so you must highlight
[tex]1368x^3 - 381x^2+3.74X+2.45[/tex]
=2.45=instant velocity

lol
oh t is 0
well this is how you would find instant acceleration at other times
[tex]4104x^2-762x+3.74[/tex]

sorry I added extra but I am just learning this so I thought it would be good practice.
 
Oh sorry I guess tex equations don't turn white
 
Besides, you used x as the variable rather than t :wink:
 
Darn I was so close to getting it right
 

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