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Find work done given time, acceleration, and mass 
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#1
Oct1810, 10:33 AM

P: 4

a box with a mass of 6.0 kg is accelerated from rest by a force across a floor at a rate of
2.2 m/s^2 for 5.9 s. Find the net work done on the box m=6.0kg a=2.2m/s^2 t=5.9 s a=0 degrees i know W=Fdcos(a) and F=ma so, F=6.0kg*2.2m/s^2=13.2N W=13.2N*d*cos0=13.2N*d I am a little unsure as how to find d though. would it be one of the kinematic equations? 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution 


#2
Oct1810, 10:44 AM

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P: 26,157

hi daltomagne!
(try using the X^{2} icon just above the Reply box ) You can either use one of the standard constant acceleration equations to find d, or you can use another of them to find v_{f}, and then apply the workenergy theorem ( work done = change in mechanical energy). 


#3
Oct1810, 11:18 AM

P: 4

so i'm thinking v=v_{i}+at and that gives me v_{i}=12.98m/s
and x_{f}=x_{i}+v_{i}t+1/2at^{2}? but that gives me a value for x=38.3 m? so something isn't adding up 


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