Calcium Sulfate Dihydrate Reaction w/ Water - Fred

[Mathman23]

Hi

I got a question regarding chemical reaction:

3 H2O + 2(CaSO4 . 1/2 H2O) ----> 2 (CaSO4 . 2H20)

calciumsulfat dihydrat reacting via water.

My question is:

If I have 1 Kilogram of calciumsulfat dihydrat how much water is needed ?

Thanks in advance.

Sincerely

Fred

 

[chem_tr]

Hello,

You'll first need to calculate how many moles of calcium sulfate dihydrate are equal to one kilogram. Then notice that there is 1,5:1 ratio between water and calcium compound, just do the necessary math to obtain the moles, and find the grams from it. Since the density of water is 1 g/mL at ambient temperature, you can directly find how many mililiters of water will be used in the reaction.

Hint: one mole of water is equal to eighteen grams, since O:16 g/mol and H:1 g/mol.

Regards, chem_tr