## Side-by-Side Blocks with Force pushing it

1. The problem statement, all variables and given/known data
Three blocks are in contact with each other on a frictionless, horizontal surface. A horizontal force F is applied to m1. If m1= 2 kg, m2= 3 kg, m3= 4 kg, and F= 18 N, find (a) the acceleration of the blocks, (b) the resultant force on each block, and (c) the magnitude of the contact forces between the blocks.

2. Relevant equations
(a) F - N12 = m1a
N21 - N23 = m2a
N32 = m3a

(b) R1 = m1a
R2 = m2a
R3 = m3a

3. The attempt at a solution
(a) I found that a= 2 m/s2

(b) R1 = 4 N
R2 = 6 N
R3 = 8 N

(c) I have no idea what "the magnitude of the contact forces between the blocks" means. Can somebody please tell me if I've done (a) and (b) right? And how to do (c)?
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 Recognitions: Homework Help Hi ifeelretarded, welcome to PF. Your part a is correct. To find the contact force, find the net force acting on each block. The net force acting on m1 is F - F1 = m1*a, here F1 is the contact force between m1 and m2. Similarity you can find tha contact force between m2 and m3.
 Recognitions: Homework Help Hi ifeelretarded, welcome to PF. Your part a is correct. To find the contact force, find the net force acting on each block. The net force acting on m1 is F - F1 = m1*a, here F1 is the contact force between m1 and m2. Similarity you can find tha contact force between m2 and m3.

## Side-by-Side Blocks with Force pushing it

 Quote by rl.bhat Hi ifeelretarded, welcome to PF. Your part a is correct. To find the contact force, find the net force acting on each block. The net force acting on m1 is F - F1 = m1*a, here F1 is the contact force between m1 and m2. Similarity you can find tha contact force between m2 and m3.
So F1 was already previously found in part (b)?
 Recognitions: Homework Help No. R1 is the net force R1 = 18N - F1. Find F1.

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