What Concentrations of KH2PO4 and Na2HPO4 are Needed to Make a pH 7.00 Buffer?

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Discussion Overview

The discussion revolves around preparing a buffer solution at pH 7.00 using KH2PO4 and Na2HPO4. Participants explore the necessary concentrations of these compounds and the application of the Henderson-Hasselbalch equation to solve the problem. The scope includes theoretical calculations and practical application in a lab context.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant asks for help in determining the concentration of Na2HPO4 needed to create a buffer at pH 7.00 with a given concentration of KH2PO4.
  • Another participant suggests using the Henderson-Hasselbalch equation but notes uncertainty about the pKa value.
  • A different participant emphasizes the importance of knowing the pKa values for the phosphate species to solve the problem accurately.
  • There is a general inquiry about whether the pKa of strong bases can be ignored, which leads to clarification that it is not applicable in this context.
  • A later post introduces a new question regarding the titration of acetic acid with KOH, seeking guidance on plotting the titration curve.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the application of the Henderson-Hasselbalch equation and the importance of pKa values. There is no consensus on the specific values needed for the calculations, and the discussion remains unresolved regarding the initial buffer problem.

Contextual Notes

Participants mention the need for specific pKa values for accurate calculations, indicating that the problem's resolution depends on this information. Additionally, there is uncertainty about the molar ratio of the conjugate base to acid in the buffer solution.

Who May Find This Useful

Students and individuals interested in buffer solutions, titration processes, and the application of the Henderson-Hasselbalch equation in chemistry may find this discussion relevant.

Gata
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can someone please help me with this problem, its giving me lots of trouble to solve :

(a) Suppose you wanted to make a buffer of exactly ph 7.00 using KH2PO4 and Na2HPO4. If you had a solution of 0.1M KH2PO4, what concentration of Na2HPO4 would you need?

(b)Now assume you wish to make a buffer at the same ph, using the same substances, but want the total phosphate molarity (HPO42-) + (H2PO4-) to equal 0.3 What concentrations of KH2PO4 and Na2HPO4 would you use?
 
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What have you tried so far ? What ideas do you have ?

Tell us what you've tried and we'll guide you the rest of the way. :smile:
 
i tried the henderson/hasselbalch equation :
the salt : Na2hpo4
the acid :kh2po4
ph= 7.0
pka ? not sure
not sure how to proceed on the second part or how to finish the first part
 
If you want to find pH, then you should use pKa of the acid in Henderson-Hasselbach equation.
In your second question, you don't know the molar ratio of conjugate base to acid. The rest is known, just find it.
 
question

its been said that the pka of strong bases are so close to 1 they ( the pka ) can be ignored.

Is this true ?
 
Yes that's correct, but it is invalid for this question, as phosphate species other than ortho-phosphoric acid (H3PO4) need pKa values. If you were not given that data, it is nearly not possible to solve the H-H equation. Please find the pKa values for them, and solve this question. It is not that difficult. But when you think you're lost, keep asking.
 
thanks

i have already solved the problem i was just asking a general question
thanks chem_tr
 
new question

I was given this lab problem calc the ph values and draw the titration curve for the titration of 500ml of 0.010m acetic acid (pka 4.76) with .010m KOH.
I have to give two points the starting ph and the equivalence point.

I found the equivalence point to be the pka ( where ph=pka ).
I know i have to calc the second point using the KA I am just not sure how to plot the x-axis and y-axis

for the y-axis i know i have to plot ph
but for the x-axis is it KOH (eq ) or what ?
im not sure
can someone help me with this one ?
 
Well, the starting pH will be the pH of the acetic acid solution with no KOH added, I am sure you are not asking this. What you're asking instead is simple, too; just plot the curve between titer (mL of KOH solution) and pH, on x and y axis, respectively.
 

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