Solving Projectile Problem: Initial Speed 100m/s, Object 5m Away 2m High

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The discussion focuses on solving a projectile motion problem where an object is launched with an initial speed of 100 m/s to clear an obstacle 5 m away and 2 m high. The user attempts to derive the angle of launch using the equations of motion, specifically y = (Vy + (1/2)(-9.8)(t^2)) and t = 5/(Vx). The user realizes that their approach leads to a complex equation, indicating a need for a more effective method to determine the launch angle.

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Im given the initial speed (100m/s) of an object launched at an unkown angle, it needs to just barely go over an object 5m away 2m high.

Ive made several attempts at this, all of which ending up in the trash
my most recent try is

y=(Vy + (1/2)(-9.8)(t^2)
t = 5/(Vx)

Then used Vx^2 = 100 - Vy^2
and subsituted it all in, and i come out with a big mess to solve, so I've assumed this is not the correct (or best) way to do this

Sorry for not going into more detail, but you should be able to get the idea
 
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BTW I am trying to find the angle...and the 100m/s is the Hypot. componet of the velocity
 
try putting Y = f(x), so you can plug your X, Y and Vo values, and solve for theta.
 

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