Designing a 64k 8 Bit Word Memory Unit with 4096x4 Chips

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SUMMARY

The design of a 64k 8-bit word memory unit requires a total of 32 memory chips, specifically 4096x4 configuration chips. Each 4096x4 chip provides 4096 addresses and 4 bits per address. To achieve the required 64k addresses, 16 chips are necessary, and since each chip only provides 4 bits, two chips are needed per address to meet the 8-bit requirement. Therefore, the total number of chips needed is 16 multiplied by 2, resulting in 32 chips.

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Hi, how do you go about figuring out how many memory chips are needed to design a memory unit that contains 64k 8 bit words and each memory chip is 4096x4?

Thanks
 
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Well, each of your 4k x 4 chips provides 4k addresses. You need 64k addresses, so you're going to need 16 of those chips just to get enough addresses. Futhermore, each chip only provides 4 bits per address, and you need 8 bits per address, so you'll need two chips per address. Thus, you'll need 16 * 2 = 32 chips.

- Warren
 

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