What is the Force on the +q Charge?

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SUMMARY

The discussion focuses on calculating the force on a charge +q located on the z-axis in the presence of a charge -2q at a distance d along the same axis. The relevant equation used is F = -1/(4πε₀) * (q₂/(2d)²). The method of images is essential for solving this problem, particularly because the xy-plane is identified as a grounded conductor, which necessitates the inclusion of a mirror charge to accurately determine the force acting on +q.

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Homework Statement


Find the force on +q . there's a graph which has +q on 3d in the z axis and -2q on d in the z axis


Homework Equations


F=-1/4pie Eo (q2/(2d)2


The Attempt at a Solution


I don't understand why you need to add mirror image of the charges to find the force.
I know how to solve the problem from there.
The answer is -1/4pieEo(29q2/72d2
 
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method of images would only be used if there was a conductive surface somewhere on that graph you are forgetting to tell us about
 
o that makes sense thanks yea it says says xy plane is grounded conductor. didnt think that matters but now i know lol
 

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