Solving Physics Homework: Mass, Slope & Speed | POWER Needed

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Homework Help Overview

The discussion revolves around a physics homework problem involving a skier being pulled up a slope, focusing on the concepts of work and power. The specific questions include calculating the work required to pull the skier up a slope and determining the necessary power of the motor for this task.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the equations relevant to calculating work, particularly in relation to potential energy. There are questions about the correct angle of the slope and the conversion of units from joules to kilojoules and horsepower.

Discussion Status

Some participants have offered guidance on focusing on potential energy and the work-energy principle. There is an acknowledgment of confusion regarding the calculations and unit conversions, with multiple interpretations of the problem being explored.

Contextual Notes

There are indications of uncertainty regarding the angle of the slope and the correct interpretation of the displacement involved. Participants also mention potential calculator errors and the need to clarify the units of measurement used in the calculations.

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POWER! its no good

alright, I'm stuck with a homework problem again!


A skier of mass 70kg is pulled up a slope by a motor-drive cable.
A) homework much work is required to pull him 60 m up a 30º slope at a contant speed of 2m/s (frictionless)?
B) what power must a motor have to perform this task?

please help. soon.
 
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maybe more specifically, I'm having a lot of trouble deciding what equation to use for work... someone want to give me a push start?
 
A) Since your kinetic energy doesn't change, you only need to consider the work necessary to increase the potential energy of the system.
B) Find the average force applied from your expression for the work done in A)
 
i guess no one wants to help me tonight... okay, thanks anyway.
 
Were you losing hope, then?..:wink:
 
sorry, i didnt see that post! so, are you talking potential energy then? like W = mgy which is W = (70)(9.8)(30)
I got y, aka h, from 60sin20. i try this and i get the wrong answer. the answer is 21kJ
 
I AM A COMPLETE IDIOT! i have been doing this problem all night and the answer is right. i guess I'm just having calculator input errors
 
anymore help with part b?
 
Three questions:
a) Is the slope 20 degrees or 30 degrees?
(You have indicated both..)

b)Have you remembered that the answer is given in kJ rather than J, which is what you will get from your calculations.
c) Perhaps you should try "up" meaning a vertical displacement of 60 meters?
 
  • #10
All right, seems like you did OK, then:
For b) follow the procedure I indicated..
 
  • #11
i'm getting the wrong answer-- the answer is .92hp... i don't know if I'm converting wrong or what. okay, you suggested average force? I'm sorry, I'm really stupid-- what's the equation for that?
 
  • #12
W=Fd, where d is the traversed distance.
IConvert W into joules perhaps; I've no idea how watts are converted into horsepower..:redface:
(Have only used N*m/s, which is watts I would think..)
 
  • #13
nevermind, i got it... yipee! time for a drink : )
 
  • #14
To your health..
 

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