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Capacitance Equivalent 
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#1
Feb1111, 04:27 PM

P: 5

1. The problem statement, all variables and given/known data
The equivalent capacitance of the capacitors shown in the figure is 9.23 MicroF 2. Relevant equations 3. The attempt at a solution So to find C I Attempted to add the Series ones across the top and the left most capacitor with the following calculation: [1/(1/c+1/12+1/8.35)]=[1/({100.2+20.35c}/100.2c)]=(100.2c)/(100.2+20.35c) then I took (100.2c)/(100.2+20.35c) and added it to 7.22 microF +4.25 microF =9.23 microF Then I got : (100.2c)/(100.2+20.35c)=2.24 100.2c=2.24*(100.2+20.35c) 100.2c= 224.448  45.584c 145.784c = 224.448 c=1.540 Which is not correct, and I'm also pretty sure that capacitors can't be negative right? 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution 


#2
Feb1111, 04:39 PM

Mentor
P: 11,683

Components are not in series if there are other components attached to the nodes that join them. In the figure, only the 12 and 8.35 microfarad capacitors are in series.



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