Capacitance Equivalent

cjames9001

1. The problem statement, all variables and given/known data
The equivalent capacitance of the capacitors shown in the figure is 9.23 MicroF



2. Relevant equations




3. The attempt at a solution

So to find C I Attempted to add the Series ones across the top and the left most capacitor with the following calculation:

[1/(1/c+1/12+1/8.35)]=[1/({100.2+20.35c}/100.2c)]=(100.2c)/(100.2+20.35c)

then I took (100.2c)/(100.2+20.35c) and added it to 7.22 microF +4.25 microF =9.23 microF
Then I got :
(100.2c)/(100.2+20.35c)=-2.24

100.2c=-2.24*(100.2+20.35c)

100.2c= -224.448 - 45.584c

145.784c = -224.448

c=-1.540
Which is not correct, and I'm also pretty sure that capacitors can't be negative right?
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution

gneill

Components are not in series if there are other components attached to the nodes that join them. In the figure, only the 12 and 8.35 microfarad capacitors are in series.