# Projected particle

by aurao2003
Tags: particle, projected
 P: 737 You have a lot of variables and no explanation of what they are. The way I would do this would be to solve the quadratic formula for h(t) - h, where h(t) is the function of time to hight, and h is the hight you're trying to find. h would be grouped with c. I can't desern the values of a, b, and c from your post, so you're gonna have to plug them in. Since you know that the quadratic equation is give the zeros of the function, and by subtracting h, you're shifting the function down, such that the new zeros are at the values of t are values that would have made h(t)=h $$\frac{-b-\sqrt{b^2-4a(c-h)}}{2a}-\frac{-b+\sqrt{b^2-4a(c-h)}}{2a}=2.4$$