
#1
Feb2111, 08:25 AM

P: 466

Find the curl of the following vector field
u = yi+(x+z)j+xy^(2)k Now using the method Ive bin taught similar to finding determinant of 3x3 matrix here is my answer i(2yx1) j(y^2) +k(0) Just looking for confirmation if this is correct or any basic errors I have made thank you. 



#3
Feb2111, 08:41 AM

P: 466

Thank you Char.limit just a follow up question I am asked:
Find (curl u).v Where v = xi+(y^(2)  1)j+(1x^(2))k Is that just the dot product of the vector v and the curl established for u. Thank you 



#4
Feb2111, 08:51 AM

PF Gold
P: 1,930

Curl of a vector field
Yes it is. And you can just ignore the k part completely.




#5
Feb2111, 08:56 AM

P: 466

So would that give me:
(2x^(2) y x) +(y^(4)  y^(2)) Also do I still need the i j k notations?? 



#6
Feb2111, 09:03 AM

Sci Advisor
HW Helper
P: 11,866

YOu have obtained a scalar. There's no more unit vector involved.




#7
Feb2111, 09:06 AM

P: 466

Oh ok so my final answer would just be 2x^(2)  x +y^(4)  y^(2)
correct? 


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