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Lorentz Force Question - Where did the y dot come from ?!

 
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Mar2-11, 02:48 PM   #1
 

Lorentz Force Question - Where did the y dot come from ?!


Basically the question is about a penning ion trap. You need to use the equation for the Lorentz Force, which I have. It says the trap electrodes have a potential:

V(x,y,z) = A(2z^2 - x^2 - y^2); There's a superimposed uniform B-Field B = B(z hat)

It then asks you to write down an expression for the z-component of the total electromagnetic force on a particle of charge q, explaining why it doesn't depend on B. I did that. It then says write down the equation of motion. I did that.

It then asks you to do the same thing with the x and y components i.e.) Find the x and y components of the total force, write down the equations of motion, etc.

But the solution shows a y dot in the equation of motion in the x-direction:

x double dot = q/m[2Ax + B(y dot)]

Where did this y dot come into it? Any ideas? I thought a V term is next to B?
Thanks guys, muchly appreciated.
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Mar2-11, 03:44 PM   #2
 
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[tex]\dot{y}[/tex] is the y-component of the velocity.
Mar2-11, 03:48 PM   #3
 
Quote by fzero View Post
[tex]\dot{y}[/tex] is the y-component of the velocity.
Thanks, I realised a few mins ago lol. The x and z cross to give the y-direction. For some reason I also thought V was potential, not velocity. It's a little v, of course.
Mar3-11, 07:02 AM   #4
 

Lorentz Force Question - Where did the y dot come from ?!


I actually disagree with their answer, shouldn't it be -y dot? x cross z gives -y, I think ...
Mar3-11, 10:55 AM   #5
 
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Quote by Physics Enemy View Post
I actually disagree with their answer, shouldn't it be -y dot? x cross z gives -y, I think ...
The equation you wrote above was for this [tex]x[/tex] component of the force, which contains [tex] (\vec{v} \times \vec{B})_x = v_y B_z[/tex].
Mar3-11, 09:02 PM   #6
 
Quote by fzero View Post
The equation you wrote above was for this [tex]x[/tex] component of the force, which contains [tex] (\vec{v} \times \vec{B})_x = v_y B_z[/tex].
Yes you're right. V x B = (V_y * B)xhat - (V_x * B)yhat + (0)zhat
So the x component is B*ydot, and y component is -B*xdot
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