Calculating the Resultant Force at J

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Homework Help Overview

The problem involves calculating the resultant force acting on point J due to three different forces: one directed north, another west, and a third at an angle of 60° east of north. The subject area pertains to vector addition in physics.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss methods for adding vectors and question the understanding of vector magnitude and direction. There are references to previous experiences with similar problems involving vector addition and the use of trigonometry to resolve components.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to resolve the vector components and questioning assumptions about the problem setup. Some guidance on using trigonometry to find components has been suggested.

Contextual Notes

There is a mention of potential confusion regarding the northeast vector and its components, indicating that participants are grappling with the specifics of vector resolution.

Kdawg
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Three forces act simultaneously on point J. One force is 20.0 N north; the second is 20.0 N west; the third is 10.0 N 60° east of north. Determine the magnitude and direction of the resultant force.
 
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Do you have any ideas yourself about how to do this? Do you know how to add vectors? Do you know what the magnitude of a vector is?
 
I know how to add vectors in a problem like "Two boys push on a box. One pushes with a force of 111 N to the east. The other exerts a force of 158 N to the north. What is the size and direction of the resultant force on the box?" Size = 193 Direction = 55. I also know this can be done by graphing the vectors and adding the x and y cordinates, I just can remeber how to get the x and y cordinates.
 
I'm assuming that only the northeast vector is a problem. It's magnitude is 10. Think of this as the length of the hypothenuse of a right triangle, and find the east (x) and north (y) components of the vectors using trigonometry (sin and cos). These components are just the other two sides of the right triangle, so I'm sure you've done this kind of thing before.
 

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