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Vector spaces |
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| Oct16-04, 11:14 AM | #1 |
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Vector spaces
I have :
c1(t+1) + c2(t^2 + 2) + c3(t^2 -t) = 0 for all t. by specifying different values of t. I get t=-1: 3c2 + 2c3=0 t=0: c1+2c2 =0 t=1:2c1 + 3c2 =0 How can I check that the only solution is c1=c2=cc3=0 ? |
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| Oct16-04, 11:26 AM | #2 |
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Simply solve the system of equations you've just made for c1,c2,c3.
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| Oct16-04, 11:27 AM | #3 |
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that's the problem I don't know how. I know it's simple but I just can't figure it out?
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| Oct16-04, 11:28 AM | #4 |
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Vector spaces
You have 3 equations in 3 unknowns; you've seen that before?
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| Oct16-04, 11:44 AM | #5 |
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I've done this when I have a matrix in reduce or reduce echelon but then I only have x1 in one linem here I have c1 in 2nd and 3rd row and it's there I am stuck. I admit I'm not very good at this. If you possibly can would you be so kind to lead my on with this problem??
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| Oct16-04, 12:05 PM | #6 |
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Why don't you just interchange line 1 and line 3?
Interchanging "topmost equation" with "bottom-most equation" can't possibly change the solution, or what? |
| Oct16-04, 12:49 PM | #7 |
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I got it. Thanks a lot
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