
#1
Mar1511, 11:58 AM

P: 27

I am not quite sure how to prove this,
I can see it involves using a double angle formula (see http://mathworld.wolfram.com/DoubleAngleFormulas.html). I have tried working backwards but to no avail. Any ideas? Uploaded with ImageShack.us 



#2
Mar1511, 01:07 PM

Engineering
Sci Advisor
HW Helper
Thanks
P: 6,388

Use
[tex]\sin a \cos b = (\sin (a+b) + \sin(ab))/2[/itex] 



#3
Mar1511, 01:12 PM

P: 27

Thanks! I will give that a go




#4
Mar1511, 01:29 PM

P: 27

Trigonometric Proof[tex] \cos a \sin b = (\sin (a+b)  \sin(ab))/2 [/tex] PROBLEM SOLVED! 


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