Trigonometric Proof

likearollings

I am not quite sure how to prove this,

I can see it involves using a double angle formula (see http://mathworld.wolfram.com/Double-AngleFormulas.html).

I have tried working backwards but to no avail.

Any ideas?



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AlephZero

Use
[tex]\sin a \cos b = (\sin (a+b) + \sin(a-b))/2[/itex]

likearollings

Thanks! I will give that a go

likearollings

Thanks, I managed to do it using

[tex]
\cos a \sin b = (\sin (a+b) - \sin(a-b))/2
[/tex]

PROBLEM SOLVED!