Kinetic Friction on inclined plane problem

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SUMMARY

The problem involves calculating the acceleration of a block on an inclined plane with a coefficient of kinetic friction of 0.20 and an angle of 60 degrees. The correct acceleration, as stated in the discussion, is 7.5 m/s². To solve this, one must utilize free body diagrams to analyze the forces acting on the block, applying Newton's Second Law, which states that the sum of all forces equals mass times acceleration (ΣF = ma). The forces include gravitational components and frictional forces derived from the angle of inclination.

PREREQUISITES
  • Understanding of free body diagrams
  • Knowledge of Newton's Second Law
  • Familiarity with trigonometric functions (sine and cosine)
  • Concept of kinetic friction and its coefficient
NEXT STEPS
  • Study the derivation of forces on an inclined plane
  • Learn how to calculate frictional forces using coefficients
  • Explore advanced applications of Newton's Laws in dynamics
  • Practice problems involving different angles and coefficients of friction
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to explain concepts of friction and motion on inclined planes.

VinnyCee
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Been trying to comprehend this one for a few hours:

The coefficient of kinetic friction between a block and an inclined plane is 0.20 and the angle is 60 degrees.

What is magnitude of a? The book says 7.5 m / s^2
How do I figure this with no speeds or distances or even a mass?
 
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you got to do your free body diagrams! those stupid things... remember? the sum of all forces = ma unless the velocity is constant. do one for the x side and one for the y side, incorporate your co. of kinetic friction and the angle (probably cos60 and sin60 from mg)... help any? i have a lot of trouble with these, too
 
Like doxi said use a freebody diagram then

Apply Newton's 2nd Law

[tex]\sum_{i=1}^{n} \vec{F}_{i} = m \vec{a}[/tex]
 

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