What is the Kinetic Energy of H-Atom in HBr Photodissociation?

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SUMMARY

The kinetic energy of the hydrogen atom (H-atom) in the photodissociation of hydrogen bromide (HBr) can be calculated using Einstein's equation, E=hv=hc/λ. By knowing the dissociation energy and the wavelength of the photons involved, one can determine the total energy (E) and subsequently solve for the kinetic energy by rearranging the equation to E = dissociation energy + kinetic energy. This method provides a definitive approach to calculating the kinetic energy in photodissociation reactions.

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Hi yall! Does anyone know how one can solve kinetíc energy of H-atom if the dissociation energy and the wavelength of photons are known when HBr-molecules are photodissociated? Tricky... :cry:
 
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I'll take a stab at this. You know by Einstein's equation E=hv=hc/Lamda.


E=dissociation energy+kinetic energy. You can find E and you are given dissociation energy, solve for kinetic energy.


Again, I am not 100% sure if this is correct.
 
At what temperature and pressure ?
 

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