Some guidance please Newton's Laws

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SUMMARY

The discussion centers on calculating the coefficient of kinetic friction and the acceleration of a crate being pushed and pulled at an angle. The coefficient of kinetic friction between the crate and the floor is established as 0.26. When the crate is pulled at an angle of 20 degrees above the horizontal, the user attempts to calculate the acceleration using the equation F = m*a, but struggles with incorporating the frictional force correctly. The correct approach involves using the normal force adjusted for the angle of the applied force to find the net force acting on the crate.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Knowledge of forces and free body diagrams
  • Familiarity with the concepts of friction and normal force
  • Basic algebra for solving equations
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  • Study the calculation of normal force in inclined scenarios
  • Learn about the relationship between frictional force and normal force
  • Explore detailed examples of free body diagrams in physics
  • Practice solving problems involving Newton's Laws with varying angles
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jlshoop
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A1000N crate is being pushed across a level floor at a constant speed by a force of 300N at an angle of 20 degrees below the horizontal.
(a) what is the coefficient of kinetic friction between the crate and the floor

I was able to find this which is = .26

(b) If the 300N force is instead pulling the block at an angle of 20 degrees above the horizontal what will the acceleration of the crate be?(assume that the coefficient of friction is the same as found in (a))

Help I need guidance on this part!
 
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Have you tried working this out yourself? Draw a freebody diagram and write the equation of motion in the horizontal direction, solve for a.
 
I was afraid it would seem that way if i didn't describe all my attempts to solve it.

I am confused, my best bet was to use the equation
F= m*a
because i know that I could find my acceleration from this formula
So I applied it using the numbers from the problem
m=w/9.8
m=897/9.8 = 91.53
F=282

282/91.53 = a = 3.1

which is not right
plus i didn't use the coefficient

So i thought, if i apply
F=μN
F=.26 * 897 = 233

then
233/91.53= 2.54
also not right

so I'm lost.
 

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