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Problem with finding an Inverse Laplace Transform |
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| Jul16-11, 04:25 PM | #1 |
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Problem with finding an Inverse Laplace Transform
I've been messing around with Laplace transforms. Anyway to get to the point I arrived at a "solution" in the s domain and got stuck.
I'm trying to solve for the inverse laplace transform of A: [tex] {\cal L}^{-1} \{A\} [/tex] where [itex] A = F(s) e^{C_2\sqrt{-s+C_1 }} [/itex] and [itex] C_1,C_2 [/itex] are constants and [itex] F(s) [/itex] is a function of s. Is there any way to apply the shifting theorem to this equation? If not how do I go about solving the above? I don't know much about [itex] F(s) [/itex]. I already applied boundary and initial conditions. Thanks. |
| Jul16-11, 07:22 PM | #2 |
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I guess I should clarify that I am trying to find [itex] {\cal L}^{-1} \{A\}=a(x,t) [/itex] for any [itex] F(s) [/itex].
In the above equation [itex] C_2 [/itex] is [itex] x [/itex]. So the equation is actually [itex] A = F(s) e^{x\sqrt{-s+C_1 }} [/itex]. I wrote [itex] C_2 [/itex] in the place of [itex] x [/itex] because I was trying to look up the transform in tables. I had specified the boundary condition as [itex] a(-\infty,t)=f(t) [/itex] This transforms to the [itex] s [/itex] domain as [itex] A(-\infty,s)=F(s) [/itex]. Is there any way to get a general form for [itex] a(x,t) [/itex] for any [itex] F(s) [/itex] or would I have to specify [itex] F(s) [/itex]? |
| Jul17-11, 06:29 PM | #3 |
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Recognitions:
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I think that the way that you're going to have to tackle this is residue calculus.
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| inverse, laplace, shifting, transform |
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