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How do calculate the current when I have the active power and reactive power and volt 
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#1
Aug1511, 02:51 PM

P: 12

How do calculate the current when I have the active power and reactive power and voltage?
A singlephase, fullwave controlled bridge rectifier supplies a permanent magnet dc motor. The rectifier is connected to a 240V ac voltage source and absorbs 1200W of active power and 1000VAR of reactive power from the source. If power loss in the rectifier is negligible how do i calucalte the armature current? 


#2
Aug1611, 08:22 AM

P: 669

RMS Active Current = Active Power / (RMS Voltage)
RMS Reactive Current = Reactive Power / (RMS Voltage) 


#3
Aug1611, 11:11 AM

P: 12

so what can I say about the value of the current in the armature?



#4
Aug1611, 11:50 AM

P: 669

How do calculate the current when I have the active power and reactive power and volt
I am unsure of what might be consuming the reactive power, perhaps the capacitor Filter you might be using. I don't think DC motor Consume any reactive power during Steady State. So, going with that, all the active power is being consumed by the DC motor.
And the Current Going into it (i.e. into the armature) Depends on whether you are using Capacitor and what size. Assuming you are using Large Sized Capacitor so that the Terminal Voltage Across the Motor is almost constant near the peak of 240*Sqrt(2), then the Current into the armature is Armature Current = 12000 / (339) = 3.53 A 


#5
Aug1611, 12:17 PM

PF Gold
P: 372

the motor windings are coils they consume reactive power to develop magnetic fields



#6
Aug1611, 12:19 PM

PF Gold
P: 372

find apparent power with real and reactive then use that to solve for current.
S^2 = root P^2 + Q^2 I = S/root3 V ? 


#7
Aug1611, 12:23 PM

P: 669




#8
Aug1611, 01:24 PM

Sci Advisor
P: 2,751

Lacking any other details, this type of question usually assumes that the current on the DC side is approximately constant due to the motor inductance, so that the line current is a square wave. Given this assumption you can actually calculate both the DC current and the (phase control) firing angle from the given data. 


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