- #1
Liferider
- 43
- 0
Hi, I'm trying to form an expression for a rectifier supplying a DC link with current, without actually rectifying a 3-phase input. Usage of the model is really only concerned with the RMS values and the active power drawn from the AC supply.
The DC link is just a capacitor so that:
dVDC/dt = (iDC - iL)/C
Based on what I've experienced with actual DC links, I chose the drawn rectifier current, iDC, to be a design constant multiplied with a function of DC voltage squared:
iDC = k*(Vpeak - VDC)2
Now, I wonder if this model can be used, i.e is there a design constant that will fit an actual rectifier?
Obviously, there is a certain relationship between Active Power/Active Current and the voltage drop on the DC link, I am just not sure if the square model here fits reality? Any comments to this is highly appreciated.
Regards, Arne Ranvik
The DC link is just a capacitor so that:
dVDC/dt = (iDC - iL)/C
Based on what I've experienced with actual DC links, I chose the drawn rectifier current, iDC, to be a design constant multiplied with a function of DC voltage squared:
iDC = k*(Vpeak - VDC)2
Now, I wonder if this model can be used, i.e is there a design constant that will fit an actual rectifier?
Obviously, there is a certain relationship between Active Power/Active Current and the voltage drop on the DC link, I am just not sure if the square model here fits reality? Any comments to this is highly appreciated.
Regards, Arne Ranvik