Projectile motion homerun question

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SUMMARY

The discussion centers on calculating the initial velocity of a baseball hit at a 45-degree angle that travels 98 meters for a homerun. Participants suggest using projectile motion equations, specifically separating the motion into x and y components. The key insight is to recognize that the height reached is 49 meters, and the total time of flight must account for both ascent and descent, effectively doubling the time calculated for the ascent. This approach leads to the determination of the initial velocity required for the ball to achieve the specified distance.

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all the problem gives me is: a batter hits a ball 98 meters for a homerun and he hit it at a 45 degree angle. what is the velocity of the ball off of the bat? assume the fence is at the same height as the balll.


how do i get the velocity of this thing? I tried getting the height which would be 49 meters and then figuring the time i would take to fall 49 meters, but I don't think that is right. any ideas?
 
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Try setting up a system of equations, one with respect to the y-component, and one to the x. A little hint: use the fact that sin(45) = cos(45).

Hope that helps! :)
 
IGeekbot said:
all the problem gives me is: a batter hits a ball 98 meters for a homerun and he hit it at a 45 degree angle. what is the velocity of the ball off of the bat? assume the fence is at the same height as the balll.


how do i get the velocity of this thing? I tried getting the height which would be 49 meters and then figuring the time i would take to fall 49 meters, but I don't think that is right. any ideas?

You're pretty close to being right. Except you also need to take into account the time it took to get up to 49 meters. In other words, multiply your time by two.
 

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