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newtons method |
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| Nov12-04, 03:22 PM | #1 |
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newtons method
i have the answer to this problem i just see why i'm not getting the same answer as my solution manuel. i Have two functtions f(x) = x and g(x) = tan(x)
and i have to find where these two functions are equal using newtons method. i subtracted the two functions to get this new function H(x) = x -tan(x) then i found the differential of this new function to be 1 - sec^2 (x). now by looking at the given graph of the first two functions i estimated the soulution to be about 4.1. then by unising newtons method i calculated two iterations and got an answer of 8.5987, which is wrong the answer is 4.493. what could i be doing wrong? i know how to use newtons method. |
| Nov12-04, 03:43 PM | #2 |
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You need to use a better first approximation.
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| Nov12-04, 04:50 PM | #3 |
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Recognitions:
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| Nov12-04, 05:30 PM | #4 |
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newtons method
x has to be between pi/2 and 3pi/2 these are the asmyspotes.
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| Nov13-04, 05:02 PM | #5 |
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| Nov13-04, 09:07 PM | #6 |
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thanks guys the last reply helped me out.
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